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Question: 1 / 410

What is the equation of the circle whose center is (3,4) and whose radius is 6?

x2 + y2 = 12

(x - 3)2 + (y - 4)2 = 72

(x + 3)2 + (y - 4)2 = 18

(x - 3)2 + (y + 4)2 = 36

The equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2. In this case, the equation using the given information would be (x-3)^2 + (y-4)^2 = 6^2.

The equation in choice A has a radius of √12, which does not match the given radius of 6.

Choice B is using the formula for a circle with center (h,k) but does not take into account the radius.

Choice C has a center at (-3,4) instead of (3,4).

Choice D correctly uses the formula for a circle with center (3,4) and radius 6.

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